;************************************* BINAURAL BEATS **************************************** ; AN IMPORTANT ISSUE IN THE STUDY OF SOUND LOCALIZATION CONCERNS THE EAR'S ABILITY TO PROCESS ; PHASE DIFFERENCES IN THE EARS. ONE WAY TO STUDY THIS PHENOMENON IS TO PRESENT TWO SINUSOIDS OF ; SLIGHTLY DIFFERENT FREQUENCIES, ONE TO EACH EAR. AT LOW FREQUENCIES THE SOUND MAY APPEAR TO ; FLUCTUATE OR BEAT SLOWLY AT A RATE EQUAL TO THE FREQUENCY DIFFERENCE BETWEEN THE TWO TONES. ; NOTE THAT THESE "BINAURAL BEATS" ARE QUITE UNLIKE THE PHYSICAL BEATS THAT CAN BE HEARD BY A SIN- ; GLE EAR. THERE, THE SMALL DIFFERENCE IN THE TWO FREQUENCIES CAUSES THE PHYSICAL STIMULUS TO WAX ; AND WANE IN INTENSITY; IF THIS FLUCTUATION IS SLOW ENOUGH, IT IS EXPERIENCED AS A BEATING SENSA- ; TION. WITH BINAURAL BEATS, HOWEVER, THE INTERACTION BETWEEN THE TWO TONES OCCURS BECAUSE OF ; SOME KIND OF INTERACTION IN THE NERVOUS SYSTEM OF THE INPUTS FROM EACH EAR. ; ONE MIGHT EXPECT THAT THESE BINAURAL BEATS WOULD OCCUR ONLY AT LOW FREQUENCIES, SINCE AT HIGHER ; FREQUENCIES IT IS DIFFICULT TO IMAGINE THAT THE NERVOUS SYSTEM CAN PRESERVE THE TEMPORAL STRUC- ; TURE OF THE WAVEFORM AT EACH EAR, A CONDITION THAT MUST BE MET FOR THEIR INTERACTION TO BE NOTICE- ; ABLE. THIS CONJECTURE IS SUPPORTED BY QUANTITATIVE MEASUREMENTS (LICKLIDER, WEBSTER, AND HEDLUN, ; 1950). THEY FOUND THAT THE BEST BINAURAL BEATS OCCURED AT FREQUENCY SEPARATIONS OF ABOUT 30HZ NEAR ; 400HZ AND MUCH SMALLER FREQUENCY SEPARATIONS AT THE HIGHER FREQUENCIES. NO BINAURAL BEATS ARE EVI- ; DENT ABOVE 1500HZ. TOBIAS (1965) FOUND THAT MEN APPEAR TO PERCEIVE BINAURAL BEATS AT HIGHER FRE- ; QUENCY THAN WOMAN, BUT THIS NEEDS MORE EXPLORATION. ; IN THIS DEMONSTRATION A 250HZ TONE IS PRESENTED TO THE RIGHT EAR, WHILE 251HZ TONE IS PRESENTED TO ; THE LEFT EAR. ;***************************************** HEADER ************************************************* sr = 44100 kr = 4410 ksmps = 10 nchnls = 2 instr 1 iamp = ampdb(p4) ;P4 = AMPLITUDE IN DB ifreq = p5 ;P5 = FREQUENCY ;P6 = PANNING FUNCTION FOR SIGNAL k1 linen iamp,.05,p3,.05 a1 oscili k1,ifreq,1 k2 oscili 1,p3,p6 kleft = sqrt (k2) kright = sqrt (1-k2) aleft = a1 * kleft aright = a1 * kright outs aleft,aright endin